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ch-02-ex-04-solution.cpp
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R1106 Programming Concept Rouaze
ch-02-ex-04-solution.cpp
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/*
* chapter-02-exercise-04.cpp
*
* Vector operations with loops
*
* Created on: Aug 19, 2012
* Author: Radu Popescu <radu.popescu@epfl.ch>
*/
#include <iostream>
int
main
(
int
argc
,
char
*
argv
[])
{
double
u
[
3
]
=
{
1.0
,
2.0
,
3.0
};
double
v
[
3
]
=
{
6.0
,
5.0
,
4.0
};
double
A
[
3
][
3
]
=
{{
1.0
,
5.0
,
0.0
},
{
7.0
,
1.0
,
2.0
},
{
0.0
,
0.0
,
1.0
}};
double
B
[
3
][
3
]
=
{{
-
2.0
,
0.0
,
1.0
},
{
1.0
,
0.0
,
0.0
},
{
4.0
,
1.0
,
0.0
}};
double
w
[
3
];
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
w
[
i
]
=
u
[
i
]
-
3.0
*
v
[
i
];
}
// x = u - v
double
x
[
3
]
=
{
0.0
,
0.0
,
0.0
};
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
x
[
i
]
=
u
[
i
]
-
v
[
i
];
}
// y = Au
double
y
[
3
]
=
{
0.0
,
0.0
,
0.0
};
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
for
(
int
j
=
0
;
j
<
3
;
++
j
)
{
y
[
i
]
+=
A
[
i
][
j
]
*
u
[
j
];
}
}
// z = Au - v
double
z
[
3
]
=
{
0.0
,
0.0
,
0.0
};
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
z
[
i
]
-=
v
[
i
];
for
(
int
j
=
0
;
j
<
3
;
++
j
)
{
z
[
i
]
+=
A
[
i
][
j
]
*
u
[
j
];
}
}
// C = 4A - 3B
double
C
[
3
][
3
];
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
for
(
int
j
=
0
;
j
<
3
;
++
j
)
{
C
[
i
][
j
]
=
4
*
A
[
i
][
j
]
-
3
*
B
[
i
][
j
];
}
}
// D = AB
double
D
[
3
][
3
]
=
{{
0.0
,
0.0
,
0.0
},
{
0.0
,
0.0
,
0.0
},
{
0.0
,
0.0
,
0.0
}};
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
for
(
int
j
=
0
;
j
<
3
;
++
j
)
{
for
(
int
k
=
0
;
k
<
3
;
++
k
)
{
D
[
i
][
j
]
+=
A
[
i
][
k
]
*
B
[
k
][
j
];
}
}
}
// Print w
std
::
cout
<<
"w is: "
;
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
std
::
cout
<<
w
[
i
]
<<
" "
;
}
std
::
cout
<<
std
::
endl
;
// Print x
std
::
cout
<<
"x is: "
;
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
std
::
cout
<<
x
[
i
]
<<
" "
;
}
std
::
cout
<<
std
::
endl
;
// Print y
std
::
cout
<<
"y is: "
;
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
std
::
cout
<<
y
[
i
]
<<
" "
;
}
std
::
cout
<<
std
::
endl
;
// Print z
std
::
cout
<<
"z is: "
;
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
std
::
cout
<<
z
[
i
]
<<
" "
;
}
std
::
cout
<<
std
::
endl
;
// Print C
std
::
cout
<<
"C is:"
<<
std
::
endl
;
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
for
(
int
j
=
0
;
j
<
3
;
++
j
)
{
std
::
cout
<<
C
[
i
][
j
]
<<
" "
;
}
std
::
cout
<<
std
::
endl
;
}
std
::
cout
<<
std
::
endl
;
// Print D
std
::
cout
<<
"D is:"
<<
std
::
endl
;
for
(
int
i
=
0
;
i
<
3
;
++
i
)
{
for
(
int
j
=
0
;
j
<
3
;
++
j
)
{
std
::
cout
<<
D
[
i
][
j
]
<<
" "
;
}
std
::
cout
<<
std
::
endl
;
}
std
::
cout
<<
std
::
endl
;
return
0
;
}
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