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conffile.py
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Fri, Aug 30, 20:24

conffile.py
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#!/usr/bin/env python
from __future__ import print_function
__all__ = [ "ConfFile", "addFile" ]
import sqlobject
import re
import os
class ConfFile(sqlobject.SQLObject):
"""
"""
def addFile(self,filename,params=None,regex_params=None,content=None):
print ("adding file " + filename)
self.prepare()
self.entries["filename"] = os.path.basename(filename)
if (content):
self.entries["file"] = content
else:
self.entries["file"] = open(filename, 'r').read()
if (regex_params):
for p in params:
lowerp = p.lower()
rp = "(" + regex_params
rp = rp.replace("%p",")(" + p)
rp = rp.replace("%v",")(.*)")
rr = "\\1\\2__BLACKDYNAMITE__" + p + "__"
# print (rp)
# print (rr)
self.entries["file"] = re.sub(rp,rr,self.entries["file"],flags=re.IGNORECASE)
# print (self.entries["file"])
filelist = self.getMatchedObjectList()
if (len(filelist) == 0):
tmp_conffile = ConfFile(self.base)
tmp_conffile.entries = dict(self.entries)
del tmp_conffile.entries['filename']
md5filelist = tmp_conffile.getMatchedObjectList()
if (len(md5filelist) != 0):
import md5
for f in md5filelist:
raise Exception("""There is already another file with same content but different name: this is an impossible situation for BlackDynamite.
The file concerned is '{0}' md5:{1}
** If you want keep going, please rename the file before insertion **
""".format(f['filename'],md5.new(f['file']).hexdigest()))
self.base.insert(self)
elif (len(filelist) == 1):
self.entries = filelist[0].entries
self.id = filelist[0].id
def __init__ (self,connection):
sqlobject.SQLObject.__init__(self,connection)
self.table_name = "configfiles"
self.types["filename"] = str
self.types["file"] = str
def addFile(filename,base,**kwargs):
cnffile = ConfFile(base)
cnffile.addFile(filename,**kwargs)
return cnffile

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