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invenio_2014_08_31_next_collection_tree.py
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Wed, Sep 4, 01:23

invenio_2014_08_31_next_collection_tree.py
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# -*- coding: utf-8 -*-
##
## This file is part of Invenio.
## Copyright (C) 2012, 2014 CERN.
##
## Invenio is free software; you can redistribute it and/or
## modify it under the terms of the GNU General Public License as
## published by the Free Software Foundation; either version 2 of the
## License, or (at your option) any later version.
##
## Invenio is distributed in the hope that it will be useful, but
## WITHOUT ANY WARRANTY; without even the implied warranty of
## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
## General Public License for more details.
##
## You should have received a copy of the GNU General Public License
## along with Invenio; if not, write to the Free Software Foundation, Inc.,
## 59 Temple Place, Suite 330, Boston, MA 02111-1307, USA.
from __future__ import print_function
from invenio.dbquery import run_sql
depends_on = ['invenio_release_1_1_0']
def info():
return "Update collection tree definition to match next structure"
def do_upgrade():
"""Change the score to the opposite order."""
def change_collections_score(id_dad, collection_list):
for i, col in enumerate(collection_list):
run_sql("UPDATE collection_collection "
"SET score=%s "
"WHERE id_son=%s AND id_dad=%s",
(i, col[0], id_dad))
son_collections = run_sql(
"SELECT cc.id_son "
"FROM collection_collection as cc, collection as c "
"WHERE cc.id_dad=%s and cc.id_son=c.id "
"ORDER BY cc.score DESC, c.name ASC",
(col[0], ))
change_collections_score(col[0], son_collections)
main_collections = run_sql(
"SELECT cc.id_son "
"FROM collection_collection as cc, collection as c "
"WHERE cc.id_dad=1 and cc.id_son=c.id "
"ORDER BY cc.score DESC, c.name ASC")
change_collections_score(1, main_collections)
def estimate():
return 1
def post_upgrade():
print(
'Running webcoll is highly recommended to update the collection tree.')

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