test_interp_speed.py
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	from scipy.interpolate import interp1d
	import numpy as np
	import timeit


	x = np.linspace(1, 10000, 5)
	f = lambda x: x**2
	y = f(x)

	xnew = 1234
	u = timeit.timeit(lambda: np.interp(xnew, x, y))
	print(u)

	u = timeit.timeit(lambda: interp1d(x, y))
	print(u)

	h = interp1d(x, y)

	u = timeit.timeit(lambda: h(xnew))
	print(u)