test_interp_speed.py
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			from scipy.interpolate import interp1d
			import numpy as np
			import timeit


			x = np.linspace(1, 10000, 5)
			f = lambda x: x**2
			y = f(x)

			xnew = 1234
			u = timeit.timeit(lambda: np.interp(xnew, x, y))
			print(u)

			u = timeit.timeit(lambda: interp1d(x, y))
			print(u)

			h = interp1d(x, y)

			u = timeit.timeit(lambda: h(xnew))
			print(u)

R4670/deprecated/miscellaneous/test_interp_speed.pyabfba2e921d7master