Page MenuHomec4science
Files F113071170

number_theory.py
No OneTemporary
Actions

File Metadata

Created
Wed, May 14, 17:38

number_theory.py
View Options

#!/usr/bin/python
# Copyright (C) 2018 by the RROMPy authors
#
# This file is part of RROMPy.
#
# RROMPy is free software: you can redistribute it and/or modify
# it under the terms of the GNU Lesser General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# RROMPy is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public License
# along with RROMPy. If not, see <http://www.gnu.org/licenses/>.
#
import numpy as np
__all__ = ['squareResonances','getLowestPrimeFactor','primeFactorize']
prime_v = []
def squareResonances(a:int, b:int, zero_terms : bool = True):
spectrum = []
a = max(int(np.floor(a)), 0)
b = max(int(np.ceil(b)), 0)
global prime_v
if len(prime_v) == 0:
prime_v = [2, 3]
if a > prime_v[-1]:
for i in range(prime_v[-1], a, 2):
getLowestPrimeFactor(i)
for i in range(a, b + 1):
spectrum = spectrum + [i] * countSquareSums(i, zero_terms)
return np.array(spectrum)
def getLowestPrimeFactor(n:int):
global prime_v
for x in prime_v:
if n % x == 0:
return x
if prime_v[-1] < n:
prime_v = prime_v + [n]
return n
def primeFactorize(n:int):
factors = []
number = n
while number > 1:
factor = getLowestPrimeFactor(number)
factors.append(factor)
number = int(number / factor)
if n < -1:
factors[0] = -factors[0]
return list(factors)
def countSquareSums(n:int, zero_terms : bool = True):
if n < 2: return (n + 1) * zero_terms
factors = primeFactorize(n)
funique, fcounts = np.unique(factors, return_counts = True)
count = 1
for fac, con in zip(funique, fcounts): #using number theory magic
if fac % 4 == 1:
count = count * (con + 1)
elif fac % 4 == 3 and con % 2 == 1:
return 0
return count + (2 * zero_terms - 1) * (int(n ** .5) ** 2 == n)

Event Timeline

c4science · Help