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fracture.py
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Tue, Apr 30, 20:17

fracture.py
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# Copyright (C) 2018 by the RROMPy authors
#
# This file is part of RROMPy.
#
# RROMPy is free software: you can redistribute it and/or modify
# it under the terms of the GNU Lesser General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# RROMPy is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public License
# along with RROMPy. If not, see <http://www.gnu.org/licenses/>.
#
import pytest
import numpy as np
import ufl
import fenics as fen
from rrompy.hfengines.linear_problem.bidimensional import \
MembraneFractureEngine as MFE
from rrompy.hfengines.linear_problem import MembraneFractureEngineNoDomain \
as MFEND
from rrompy.solver.fenics import affine_warping
@pytest.mark.xfail(reason = "no graphical interface")
def test_fracture():
mu0 = [45. ** .5, .6]
solver2 = MFE(mu0 = mu0, H = 1., L = .75, delta = .05, n = 20,
verbosity = 0)
uh2 = solver2.solve(mu0)[0]
solver1 = MFEND(mu0 = mu0, H = 1., L = .75, delta = .05, n = 20,
verbosity = 0)
uh1 = solver1.solve(mu0[0])[0]
L = mu0[1]
y = fen.SpatialCoordinate(solver1.V.mesh())[1]
warp1, warpI1 = affine_warping(solver1.V.mesh(),
np.array([[1, 0], [0, 2. * L]]))
warp2, warpI2 = affine_warping(solver1.V.mesh(),
np.array([[1, 0], [0, 2. - 2. * L]]))
warp = ufl.conditional(ufl.ge(y, 0.), warp1, warp2)
warpI = ufl.conditional(ufl.ge(y, 0.), warpI1, warpI2)
solver1.plotmesh([warp, warpI], show = False, figsize = (7, 7))
solver1.plot(uh1, [warp, warpI], what = 'REAL', show = False)
from matplotlib import pyplot as plt
plt.close('all')
assert np.isclose(
solver1.norm(solver1.residual(mu0[0], uh1), dual = True)[0],
solver2.norm(solver2.residual(mu0, uh2), dual = True)[0],
atol = 1e-5)
assert np.isclose(solver1.norm(uh1 - uh2), 0., atol = 1e-6)

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