yields from Cescutti

In my recent model the r-process yields for Ba are determine by just 2 values:

value1=0.8e-6 # mass fraction value2=0.3e-8 # mass fraction

value1 for 8 solar mass, value2 for 10 solar mass up to 30 solar mass.

This is the mass fraction of the newly produced Ba, so if you want the mass you should multiply for the total ejecta mass by the star considered

Just a comment. Clearly this are an addiction to any tables of yields you are using, so to be really precise you can also decrease the production in mass of ejected H by the amount you are "using" for this r-process (taking the idea that is the H the element that built up this Ba, which can be not necessarily true)

According to the hypothesis that this are pure r-process yields there is just factor of difference between Ba and Sr which is

costSr=3.16 * 88./138.

Now I will check whether the yield of Fe you are using are "compatible" with my Fe yields and I need also the SNIa yields for Fe you are using.

Gab

costBa=1.00   
    costSr=3.16 * 88./138.
    costLa=0.136* 1.
    costZr=2.53 * 90./138.
    costEu=0.117*151./138.
    costY =1.625* 89./138.

Dear Pascale and Yves,

I just want to finalize the infos regarding the r-process yields

• actually it is better to say yields from massive stars -

for the neutron capture elements we discussed.

So, the yields for Barium (newly produced fraction of Ba) should be slightly decreased, due to the combination of the different iron yields and IMF by a factor of 1.5, so:

value1=.8e-6/1.5 value2=.3e-8/1.5

Concerning the scaling factors for the the other elements, these are the numbers:

costBa=1.00 costSr=3.16 * 88./138. costEu=0.117*151./138. /2. ! extra term for obs Ba/Eu costY =1.625* 89./138. /1.6 ! extra term for obs Ba/Y

So in order to reproduce at best the plateu seen low metallicity abundance data for Eu/Ba and Y/Ba (but not extremely low with the pure r-process signature) it is important to change slightly the r-process residual ratios at the solar metallicity, (Original r-process ratio which are the numbers in black).

Philosophically speaking, it could be seen "upside down" so Sr and Ba (and partially Y) are produced more compared to the pure r-process, normalizing everything to Eu; probably, this last sentence makes more sense from the point of view of a standard nucleosynthesis but it does not change the final results.

Ciao! Gabriele

ps Just an extra comment, regarding the [Eu/Fe] - [alpha/Fe] & [Ba/Fe] abundances in Fornax. They are really puzzling!