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cosolver/FM/FMconvert/fminFM.chk
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fminFM.chk
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Case 1. Call FM_FIND_MIN to find a relative minimum between 1 and 2
for f(x) = X**3 - 9*X + 17.
Use KPRT = 0, so no output will be done in the routine, then
write the results from the main program.
A minimum for function 1 is
x = 1.7320508075688772E+00, f(x) = 6.6076951545867360E+00
Case 2. Find a relative maximum between -5 and 1.
Use KPRT = 1, so FM_FIND_MIN will print the results.
FM_FIND_MIN. Function 1 16 iterations. A relative maximum on interval
-5.0000000000E+00 to 1.0000000000E+00 is
x = -1.7320508075688772E+00, f(x) = 2.7392304845413264E+01
Case 3. Find a relative maximum between -5 and 5.
Use KPRT = 2, so FM_FIND_MIN will print all iterations,
as well as the final results.
FM_FIND_MIN. Begin trace of all iterations.
Search for a relative maximum on the interval
-5.0000000000E+00 to 5.0000000000E+00
J = 1 X = -1.1803398874989486E+00 F(X) = 2.5978606800437433E+01
J = 2 X = 1.1803398874989486E+00 F(X) = 8.0213931995625689E+00
J = 3 X = -2.6393202250021028E+00 F(X) = 2.2368347645024215E+01
J = 4 X = -1.4410524493997139E+00 F(X) = 2.6976936181159068E+01
J = 5 X = -1.6746424834205829E+00 F(X) = 2.7375369005904350E+01
J = 6 X = -1.7563668929907299E+00 F(X) = 2.7389218128504051E+01
J = 7 X = -1.7328958134121939E+00 F(X) = 2.7392301134575852E+01
J = 8 X = -1.7319129362489494E+00 F(X) = 2.7392304746644818E+01
J = 9 X = -1.7320524430474145E+00 F(X) = 2.7392304845399366E+01
J = 10 X = -1.7320507964712586E+00 F(X) = 2.7392304845413264E+01
J = 11 X = -1.7320508075473249E+00 F(X) = 2.7392304845413264E+01
J = 12 X = -1.7320508075688756E+00 F(X) = 2.7392304845413264E+01
J = 13 X = -1.7320508075688772E+00 F(X) = 2.7392304845413264E+01
J = 14 X = -1.7320508075688772E+00 F(X) = 2.7392304845413264E+01
J = 15 X = -1.7320508075688772E+00 F(X) = 2.7392304845413264E+01
J = 16 X = -1.7320508075688772E+00 F(X) = 2.7392304845413264E+01
J = 17 X = -1.7320508075688772E+00 F(X) = 2.7392304845413264E+01
FM_FIND_MIN. Function 1 17 iterations. A relative maximum on interval
-5.0000000000E+00 to 5.0000000000E+00 is
x = -1.7320508075688772E+00, f(x) = 2.7392304845413264E+01
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